Tony Morris wrote:
Is there a canonical function for traversing the spine of a list?I could use e.g. (seq . length) but this feels dirty, so I have foldl' (const . const $ ()) () which still doesn't feel right. What's the typical means of doing this?
(seq . length) doesn't sound that bad to me. Martijn. _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
