Thanks Neil ...
> Are you doing this to learn Haskell, learn about drawing lines, or to just > get it implemented? If either of the latter two, when drawing a straight > line you shouldn't need to do floating point operations such as this: Actually, my reasons are first and third. > newY = y1 + round (slope * (fromIntegral (newX - x1))) > http://rosettacode.org/wiki/Bresenham%27s_line_algorithm#Haskell Thanks for the link. > As to how to cope with the dy > dx case in your code given the dx > dy case, > you could just swap the x and y coords at the start, then swap back the x and > y coords of all the output points afterwards. Odd, but effective :-) Slope would differ right for both case right? Regards, Kashyap
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