On Thu, Sep 10, 2009 at 11:47 AM, Roman Cheplyaka <[email protected]> wrote: > step x g a = g (f a x) > > is, thanks to currying, another way to write > > step x g = \a -> g (f a x)
I thought currying just meant curry f x y = f (x,y) Isn't the reason that f x y z = body is the same as f = \x -> \y -> \z -> body just cause the former is syntactic sugar of the latter? _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
