Magicloud, There are numerous ways to construct such a function. Hoogling "(Fractional a, Integral b) => a -> b" brings up a host of functions that would be of use here in combination with fromIntegral.
Thomas On Mon, Sep 28, 2009 at 11:11 PM, Magicloud Magiclouds <magicloud.magiclo...@gmail.com> wrote: > Hi, > Here is an example: > let l = fun num in > if isIntegral l > then l > else 0 > How to do the isIntegral thing? > > On Tue, Sep 29, 2009 at 1:58 PM, Magicloud Magiclouds > <magicloud.magiclo...@gmail.com> wrote: >> Hi, >> In other weak-type language, `round i == i` would work. But in >> haskell, what should I do? Thanks. >> -- >> 竹密岂妨流水过 >> 山高哪阻野云飞 >> > > > > -- > 竹密岂妨流水过 > 山高哪阻野云飞 > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe > > _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
