On Wed, Oct 07, 2009 at 08:44:27PM -0400, Jason McCarty wrote: > Daniel Fischer wrote: > > Am Mittwoch 07 Oktober 2009 23:51:54 schrieb Joe Fredette: > > > I generally find semirings defined as a ring > > > structure without additive inverse and with 0-annihilation (which one > > > has to assume in the case of SRs, I included it in my previous > > > definition because I wasn't sure if I could prove it via the axioms, I > > > think it's possible, but I don't recall the proof). > > > > 0*x = (0+0)*x = 0*x + 0*x ==> 0*x = 0 > > This proof only works if your additive monoid is cancellative, which > need not be true in a semiring. The natural numbers extended with > infinity is one example (if you don't take 0*x = 0 as an axiom, I think > there are two possibilities for 0*∞).
Given that x = 1*x = (0+1)*x = 0*x + 1*x = 0*x + x we can show that x = x + 0*x (right) x = 0*x + x (left) so, by definition of 'zero', we have that 0*x is a zero. But we can easily prove that there can be only one zero: suppose we have two zeros z1 and z2; it follows that z1 = z1 + z2 = z2 So 0*x = 0. Any flaws? -- Felipe. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
