fmap (<*>) :: m (n (a -> b)) -> m (n a -> n b) so
f <**> x = (fmap (<*>) f) <*> x On Mon, Oct 12, 2009 at 9:22 AM, Kim-Ee Yeoh <a.biurvo...@asuhan.com> wrote: > > Does anyone know if it's possible to write the following: > > <**> :: (Applicative m, Applicative n) => > m (n (a->b)) -> m (n a) -> m (n b) > > Clearly, if m and n were monads, it would be trivial. > > Rereading the original paper, I didn't see much discussion > about such nested app. functors. > > Any help appreciated. > > -- > View this message in context: > http://www.nabble.com/%3C**%3E-for-nested-applicative-functors--tp25858792p25858792.html > Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com. > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe >
_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
