2009/10/22 zaxis <z_a...@163.com>: > >>>replace k v xs = (k,v) : filter ((/=v) . fst) xs > Great ! thanks you very much
I'm not sure why you're so much happy: Assume some function defined as follow: foo a b c = e x y z a b c where x = some constant y = some other constant z = some other constant 'e' means just that the complete body of the function foo involves x, y, z, a, b and c. Generalizing foo to let the caller choose the values of x, y, z is just foo a b c x y z = e x y z a b c -- the where is unneeded In fact, this is what functions are made for: generalizing a given expression so that part of the expression can be given in arguements. E.g. turning e a b into f a = e a b Cheers, Thu _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe