On Thu, Nov 12, 2009 at 8:52 PM, Andrew Coppin <andrewcop...@btinternet.com> wrote:
> I just meant it's not immediately clear how > foo :: forall x. (x -> x -> y) > is different from > foo :: (forall x. x -> x) -> y > It takes a bit of getting used to. That still confuses me. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
