> Doesn't haddock define __HADDOCK__ by itself? That appears to be a common misconception. The discussion on this ticket [1] indicates that haddock does *not* define __HADDOCK__. So I can not rely on it being defined. Therefore I would like to define it myself, but only in the case that haddock is being run on my code.
1 - http://trac.haskell.org/haddock/ticket/76 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
