I just mean syntax. For example. the following code snippet is C-style. In
vim, i can use `shift+%` to jump between `{' and `}', and so on.
hitSSQ hitNum = do {
nums <- fmap str_ints_pick $ readFile "ssqNum.txt";
forM_ nums (\n -> do {
let { hitB = if (n!!6 == hitNum!!6) then 1 else 0 ;
hitR = foldl (\acc x -> if(elem x (init hitNum)) then acc+1 else
acc) 0 (init n);};
printf "%s\t%d:%d\t%s\n" (show n) (hitR::Int) (hitB::Int) (hit_desc
hitR hitB);
});
}
Dietrich Epp-2 wrote:
>
> I think Miljenovic was asking about this (I removed explicit braces):
>
> fac n = let f = foldr (*) 1 [1..n] in f
>
> Which is strictly equivalent to:
>
> fac n = foldr (*) 1 [1..n]
>
> Translated into C, this is kind of like doing this:
>
> int add(int x, int y)
> {
> int sum = x + y;
> return sum;
> }
>
> instead of this:
>
> int add(int x, int y)
> {
> return x + y;
> }
>
> I find it very cumbersome (though not *difficult*) and painful to use
> a C style of programming with Haskell, so I am not sure what you mean
> when you ask why Haskell supports C style. Are you talking about
> mutable state, syntax, or something else?
>
> --Dietrich
>
> On 2010 March 27, at 4:28, zaxis wrote:
>
>>
>> Of course, you are wrong ! C is VERY important for almost every
>> programmer
>> in the world! Why cannot C programmer use haskell ? And Why does
>> haskell
>> support C code style ?
>>
>>
>> Ivan Miljenovic wrote:
>>>
>>> zaxis <[email protected]> writes:
>>>
>>>>>> Why do you bother with the interior definition of f in there?
>>>> Because i want to try a C code style not layout style without `do`
>>>> syntax
>>>> sugar .
>>>
>>> Haskell /= C, so stop trying to code as if it is. If you like C so
>>> much, then use C.
>>>
>>> --
>>> Ivan Lazar Miljenovic
>>> [email protected]
>>> IvanMiljenovic.wordpress.com
>>> _______________________________________________
>>> Haskell-Cafe mailing list
>>> [email protected]
>>> http://www.haskell.org/mailman/listinfo/haskell-cafe
>>>
>>>
>>
>>
>> -----
>> fac n = let { f = foldr (*) 1 [1..n] } in f
>> --
>> View this message in context:
>> http://old.nabble.com/Why-is-it-so-different-between-6.12.1-and-6.10.4_1---tp28049329p28051693.html
>> Sent from the Haskell - Haskell-Cafe mailing list archive at
>> Nabble.com.
>>
>> _______________________________________________
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>
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>
>
-----
fac n = let { f = foldr (*) 1 [1..n] } in f
--
View this message in context:
http://old.nabble.com/Why-is-it-so-different-between-6.12.1-and-6.10.4_1---tp28049329p28056674.html
Sent from the Haskell - Haskell-Cafe mailing list archive at Nabble.com.
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