First of all, your function
func (x,y) s dg =((x*(cos dg) - y*(sin dg)),(x*(sin dg) - y*(cos dg)))
does NOT work for type (Float -> Float), unless you mean that that is
the type of the unused parameter s. Also, your desired type ((Float ->
Float) -> Bool) itself looks suspicious. It must accept any function
(without something to apply it to) and arbitrarily return True or False.
How will you decide which? I suspect you need another parameter for this
function.
Second, on the off chance you are trying to calculate the position on a
circle scaled then rotated an angle dg from (x,y), that new position is
f (x,y) s dg = (s*(x*(cos dg) - y*(sin dg)),s*(x*(sin dg) + y*(cos dg)))
in which case you are missing the s and the last minus sign in your
formula should be a plus sign.
If so, this can be evaluated with greater clarity (and probably
accuracy) in polar coordinates:
g (x,y) s dg = (r * cos a, r * sin a)
where r = s * sqrt (x^2 + y^2)
a = atan2 y x + dg
Third, if you did not need the scale, I would use an underscore to make
that clear:
h (x,y) _ dg = (r * cos a, r * sin a)
where r = sqrt (x^2 + y^2)
a = atan2 y x + dg
That's all the observations I can make unless you describe the problem
more clearly. Sorry.
Dan
Mujtaba Boori wrote:
sorry
ok I am trying to make these calculation
func (x,y) s dg =((x*(cos dg) - y*(sin dg)),(x*(sin dg) - y*(cos dg)))
This work for type (Float -> Float)
but how can make it work with ((Float -> Float) -> Bool)
because my main function that I want use with. it takes (Float,Float)
->Bool) I need to return the same type ((Float,Float) ->Bool) so it
could be used with other function.
On Mon, Apr 19, 2010 at 5:54 PM, Ozgur Akgun <ozgurak...@gmail.com
<mailto:ozgurak...@gmail.com>> wrote:
Can you at least give an example of how you intend to use this "func"?
Since you do not describe it's behaviour, it is very hard to make a
useful
comment (at least for me)
Best,
On 19 April 2010 16:54, Mujtaba Boori <mujtaba.bo...@gmail.com
<mailto:mujtaba.bo...@gmail.com>> wrote:
>
> Hello
> I am sorry for the silly question.
>
> I have a function as the following
> func:: ((Float,Float) ->Bool) -> Float -> ((Float,Float) -> Bool)
> I am trying to make calculation in this type ((Float,Float)
->Bool) with Float and then pass the information to ((Float,Float)
-> Bool)
>
> Thank again appreciated.
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--
Ozgur Akgun
--
Mujtaba Ali Alboori
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