There is the ChristmasTree package (http://hackage.haskell.org/package/ChristmasTree) which provides a very fast read alternative by deriving grammars for each datatype. If you want to know the speed differences, see http://www.cs.uu.nl/wiki/bin/view/Center/TTTAS for more information (it's in the Haskell Do You Read Me paper, see section 5 for a comparison of efficiency).
-chris On 9 mei 2010, at 05:32, Tom Hawkins wrote: > I have a lot of structured data in a program written in a different > language, which I would like to read in and analyze with Haskell. And > I'm free to format this data in any shape or form from the other > language. > > Could I define a Haskell type for this data that derives the default > Read, then simply print out Haskell code from the program and 'read' > it in? Would this be horribly inefficient? It would save me some > time of writing a parser. > > -Tom > _______________________________________________ > Haskell-Cafe mailing list > [email protected] > http://www.haskell.org/mailman/listinfo/haskell-cafe _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
