That's totally false. You don't evaluate 'undefined' before calling 'id'. (Or if you, it's because you've made a transformation that is valid because 'id' is strict.)
On Mon, May 24, 2010 at 9:05 AM, Alexander Solla <a...@2piix.com> wrote: > Yes, but only because it doesn't work at all. Consider that calling > >> id undefined > > requires evaluating undefined before you can call id. The program will > "crash" before you ever call id. Of course, the identity function "should" > have produced a value that crashed in exactly the same way. But we never > got there. _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
