Can someone provide a hand calculation of:
span (< 0) [-1, -2, -3, 0, 1, 2, -3, -4, -5]?
I know the result is ([-1, -2, -3], [0, 1, 2, -3, -4, -5]), but the recursion
flummoxes me.
Here's the Prelude definition:
mySpan :: (a -> Bool) -> [a] -> ([a], [a]) mySpan _
[] = ([], []) mySpan p xs@(x:xs') | p x
= (x:ys, zs) | otherwise = ([], xs)
where (ys, zs) = mySpan p xs'
Thanks.
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