Can someone provide a hand calculation of:
    span (< 0) [-1, -2, -3, 0, 1, 2, -3, -4, -5]?
I know the result is ([-1, -2, -3], [0, 1, 2, -3, -4, -5]), but the recursion 
flummoxes me.
Here's the Prelude definition:
    mySpan                     :: (a -> Bool) -> [a] -> ([a], [a])    mySpan _ 
[]                =  ([], [])    mySpan p xs@(x:xs')        | p x               
   =  (x:ys, zs)        | otherwise            =  ([], xs)                      
         where                                   (ys, zs) = mySpan p xs'
Thanks.
                                          
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