alts :: [a] -> [a] alts xs = map fst . filter snd $ zip xs (cycle [False, True])
Prelude> alts [0, 1..5] [1,3, 5] On Sunday Jun 6, 2010, at 10:46 AM, R J wrote: > What's the cleanest definition for a function f :: [a] -> [a] that takes a > list and returns the same list, with alternate items removed? e.g., f [0, 1, > 2, 3, 4, 5] = [1,3,5]? > > > The New Busy is not the old busy. Search, chat and e-mail from your inbox. > Get started. _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
