The answer is still applicative. :) On Monday Jul 26, 2010, at 10:06 AM, Kevin Jardine wrote:
> On Jul 26, 3:49 pm, Kevin Jardine <kevinjard...@gmail.com> wrote: >> I find >> myself wishing that f (m [a]) just automatically returned m f([a]) >> without me needing to do anything but I expect that there are reasons >> why that is not a good idea. > > Or is there a monadic list module where f(m [a]) = m f ([a]) ? > > It occurs to me that Haskell provides the tools to construct such a > module (I think) so probably one exists? > > Kevin > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
