On 16 September 2010 01:58, Thomas Davie <tom.da...@gmail.com> wrote: >> Firstly, as far as i can tell, one cannot declare a type synonym to be an >> instance of a type class, thus how would you make it an instance of >> Arbitrary? > > The standard solution here is to create a newtype, and generate them instead.
I've also written and used dedicated generation functions (especially for Strings, since I don't want _really_ arbitrary strings since some of them might accidentally bring up formatting that my parser can't cope with (or will parse as something else). Note that this is more for generating sub-parts of other data types, rather than for types I want to be able to run QC tests on. -- Ivan Lazar Miljenovic ivan.miljeno...@gmail.com IvanMiljenovic.wordpress.com _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
