Not the most efficient, but easy to understand:
genbin 0 = []
genbin 1 = ["0", "1"]
genbin i =
map ('0' :) x ++ map ('1' :) x
where
x = genbin $ i - 1
On Fri, Oct 15, 2010 at 2:21 PM, rgowka1 <[email protected]> wrote:
> Hi -
>
> How can I generate all binary string of a given length? The type
> signature would something like -
>
> genbin :: Int -> [String]
>
> For example genbin 2 would give ["00","11","01","10"] and genbin 3
> would give ["000","001","010","011","100","101","110","111"] etc..
>
> thanks..
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