Hello Dmitri, It seems that your format pattern does not match exactly the format of the input, thus the parser returns Nothing.
Try the following format string which seems to work with your date: parseTime defaultTimeLocale "%m/%d/%Y %l:%M:%S %p" ds :: Maybe UTCTime returns : Just 2009-10-11 19:04:28 UTC The parsings errors in your format could come from . %D expects a 2 char year . %H expects a 0 padded hour (like 07, not 7) Regards, Vincent Gerard On Wed, 15 Jun 2011 00:33:56 +0400 "Dmitri O.Kondratiev" <[email protected]> wrote: > I am trying to convert data string to time: > > import Data.Time > import Data.Time.Format > import Locale > > ds = "10/11/2009 7:04:28 PM" > t = parseTime defaultTimeLocale "%D %H:%M:%S %p" ds :: Maybe UTCTime > > and get "Nothing". > What is wrong? > > Thanks ! > Dmitri. _______________________________________________ Haskell-Cafe mailing list [email protected] http://www.haskell.org/mailman/listinfo/haskell-cafe
