> I haven't followed the thread carefully but why does the bird have to be a
penguin?
A bird doesn't have to be a penguin :
*instance* (Penguin b) => Bird b where
fly = -- fly method for penguins
Says that every Penguin is a Bird.
But thinking back about it, there is a problem when trying to define the
method walk, because:
class Penguin p where
walkPenguin :: ....
instance (Penguin b) => Bird b where
fly = .....
walk = walkPenguin
is kind of awful, because walk has to be duplicated. So, not the best way to
go...
2011/7/19 Maciej Marcin Piechotka <[email protected]>
> On Tue, 2011-07-19 at 01:13 +0200, Yves Parès wrote:
> > Oh, I got it: You want to have:
> >
> > class Bird b where
> >
> > class Penguin p where
> >
> > instance (Penguin b) => Bird b where
> > fly = -- fly method for penguins
> >
>
> I haven't followed the thread carefully but why does the bird have to be
> a penguin?
>
> ----------
>
> As a side note - I agree with Christopher Done that the answer is that
> you shouldn't require for bird to fly.
>
> Regards
>
> _______________________________________________
> Haskell-Cafe mailing list
> [email protected]
> http://www.haskell.org/mailman/listinfo/haskell-cafe
>
>
_______________________________________________
Haskell-Cafe mailing list
[email protected]
http://www.haskell.org/mailman/listinfo/haskell-cafe