On Mon, Oct 3, 2011 at 3:50 PM, Roel van Dijk <vandijk.r...@gmail.com> wrote: > {- forgot to reply to list -} > > This isn't Haskell syntax. Atleast not directly. It is either > hsc2hs[1] or c2hs [2]. Also see [3] for the difference between the > two. Soin order to compile that code you first have to run it through > aspecial preprocessor. > 1 - http://www.haskell.org/ghc/docs/7.2.1/html/users_guide/hsc2hs.html2 > - http://www.cse.unsw.edu.au/~chak/haskell/c2hs/3 - > http://stackoverflow.com/questions/6009031/difference-between-hsc2hs-and-c2hs > 2011/10/3 Magicloud Magiclouds <magicloud.magiclo...@gmail.com>: >> Hi, >> I am learning to use data-flags, and got this example code: >> import Data.Flags >> newtype MyFlags = MyFlags CInt deriving (Eq, Flags) >> #{enum MyFlags, MyFlags >> , myFlag1 = C_FLAG1 >> , myFlag2 = C_FLAG2 >> , myFlag3 = C_FLAG3 >> } >> >> I modified it trying to compile it. Well, I got illegal syntax at "#{e". >> In fact, I am not quite know the syntax here. Any clue? > > _______________________________________________ > Haskell-Cafe mailing list > Haskell-Cafe@haskell.org > http://www.haskell.org/mailman/listinfo/haskell-cafe >
I see. I was mislead, did not noticed the c binding part. Thank you. -- 竹密岂妨流水过 山高哪阻野云飞 _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe