Bas van Dijk wrote: > Hello, > > I'm trying to make the following faster: > > Data.Vector.Generic.fromList list > > where 'list' is some expression yielding a list.
Unfortunately, I don't think that's possible. The problem is that you 'list' will be expressed in terms of foldr/build and fromList would have to produce a Stream, i.e., basically an unfoldr. But AFAIK, there is no unfoldr/build fusion rule. There is one the other way round and vector makes use of that in toList. Roman _______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
