"+= a[i]" is the same as "+=1", isn't it?
(i accidentally didn't reply to the list on my first try. sorry.) Am 05.02.2012 16:36, schrieb Haisheng Wu:
Sorry there is a mistake in the problem description. Here it is in Python: a = [1,1,1,1] b = [0,1,2,3] c = [0,2] d = [0,0,0,0] for i in b: for j in c: if (i+j)<3: d[i+j] += a[i] -Haisheng On Sun, Feb 5, 2012 at 2:28 PM, Haisheng Wu<fre...@gmail.com> wrote:a = [1,1,1,1] b = [0,1,2,3] d = [0,0,0,0] for i in b: for j in c: if (i+j)<3: d[i+j] += a[i] My just work implementation in Haskell http://hpaste.org/57452 Another people implementation in Haskell with Monad and it turns out complex and very imperatively. http://hpaste.org/57358 Do you have any cool solution in FP way? Thanks. -Simon_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
_______________________________________________ Haskell-Cafe mailing list Haskell-Cafe@haskell.org http://www.haskell.org/mailman/listinfo/haskell-cafe
