On Sun, Mar 25, 2012 at 2:01 PM, TP <paratribulati...@free.fr> wrote:
> Hello,
>
> My primary problem may be reduced to adding elements of two lists:
> [1,2,3] + [4,5,6] = [5,7,9]
>
> My first idea was to declare a list of Int as an instance of Num, and define
> (+)
> in the correct way.
> However, it seems it is not possible to do that:
>
> -------------------
> instance Num [Int] where
> l1 + l2 = ....
> -------------------
>
> Why?
> It seems it is necessary to do:
>
> ------------------
> newtype ListOfInt = ListOfInt { getList :: [Int] }
> deriving (Show, Eq)
>
> instance Num ListOfInt where
> l1 + l2 = ...
> -------------------
>
> Am I correct? Is it the best way to do that?
>
> Now, what is the most usual way to implement l1+l2?
> I have just read about applicative functors, with which I can do:
>
> -------------------
> import Control.Applicative
> let l1 = [1,2,3]
> let l2 = [4,5,6]
> print $ getZipList $ (+) <$> ZipList l1 <*> ZipList l2
> [5,7,9]
> -------------------
>
> Is it the correct way to do that?
> I have tried:
>
> -------------------
> instance Num ListOfInt where
> l1 + l2 = ListOfInt $ getZipList $ (+) <$> ZipList (getList l1) <*>
> ZipList (getList l2)
> -------------------
>
> Isn't it too much complicated?
>
> Thanks
>
> TP
>
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> Haskell-Cafe@haskell.org
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A simple solution is to use the zipWith[1] function:
zipWith (+) [1,2,3] [4,5,6] == [5,7,9]
It takes a bit of time to get acquainted with all of the incredibly
convenient functions in base, but once you know them, it can greatly
simplify your code.
Michael
[1]
http://hackage.haskell.org/packages/archive/base/4.5.0.0/doc/html/Prelude.html#v:zipWith
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