I think you can use for for this purpose, yes? On Jan 5, 2014, at 3:07 PM, Luke Tomlin <[email protected]> wrote:
> Hello, > > I'm a newbie to pipes, and I'm having a little trouble. > > I would like to accumulate all of the 'produce' from a producer into a list, > and then yield this new list onwards. I know that my producer will produce a > finite amount of items! > > Eg. something like: > > accum :: Pipe a [a] m r > > Apologies if the solution is really obvious and I'm just being dense! > > Thanks, > > Luke > > -- > You received this message because you are subscribed to the Google Groups > "Haskell Pipes" group. > To unsubscribe from this group and stop receiving emails from it, send an > email to [email protected]. > To post to this group, send email to [email protected]. -- You received this message because you are subscribed to the Google Groups "Haskell Pipes" group. To unsubscribe from this group and stop receiving emails from it, send an email to [email protected]. To post to this group, send email to [email protected].
