The bang pattern proposal [1] still allows (!) to be used as an
operator. I think there should be no difference in this regard between !
and ~, since they are used in exactly the same location.
In my opinion the best thing would be to allow (~) and (@) as operators.
With the same restriction on definition as (!), i.e. they must be
defined in function style, not as an operator.
The change to the syntax would be to remove @ and ~ from the reserved
operators list [2],
reservedop -> .. | : | :: | = | \ | | | <- | -> | @ | ~ | =>
making it
reservedop -> .. | : | :: | = | \ | | | <- | -> | =>
Oh, and while we are at it, I think (:) should also be removed as a
reservedop, there is no reason for it to be on that list.
Twan
[1] Bang Patterns, Haskell-prime wiki
http://hackage.haskell.org/trac/haskell-prime/wiki/BangPatterns
[2] Haskell 98 report, lexical structure, identifiers and operators
http://haskell.org/onlinereport/lexemes.html#sect2.4
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