Hi,
At the outset I would like to mention that I do not completely understand
how type-class instance resolution works, and why it works that way. I have
tried reading up, but I don't completely understand WHY it works that way.
So, please feel free to ask me to RTFM if what I'm about to say doesn't
make any sense, although TFM doesn't make sense to me!
>From a pragmatic standpoint is there any way to express the following idea
in Haskell (or a future version of Haskell), **with minimal amount of
boilerplate**
If a type has an instance of type-class `a`, then here's how you can
get an instance of type-class `b`
Without the ability to express this idea, you end up with a **lot** of
type-class boilerplate, (even if you use GHC Generics) eg:
data State = data State = Inactive | Incomplete | Deleted | Trial |
Unpaid | Paid
deriving (Eq, Show, Generic)
instance AppEnum State where
toString = gEnumToString
fromString = gEnumFromString
-- You are still forced to do the following for **every single type**
even though, conceptually, this can be driven by a rule
instance ToJSON State where
toJSON s = toJSON $ toString x
instance FromJSON State where
parseJSON (Aeson.String s) = fromString s
parseJSON _ = fail "unexpected type"
instance FromFIeld State where
fromField _ mBS = case mBS of
Nothing -> fail "not expecting a NULL/Nothing"
(Just bs) -> pure $ fromString bs
instance ToField State where
toField s = toField $ toString s
I tried talking to people on IRC and also trawling StackOverflow [1] and my
take-away is essentially, that Haskell cannot express this idea. However,
my submission is, that it is a very useful idea to express and probably the
next version of the language should do something to make the lives of
programmers a little easier.
[1]
https://stackoverflow.com/questions/3213490/how-do-i-write-if-typeclass-a-then-a-is-also-an-instance-of-b-by-this-definit
-- Saurabh.
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