> > Sorry I am being a pain, just trying to understand.
> > the error is:
> > Function main has the type [(Prelude.IO ())] instead of IO ().
>
> Yes, main must return an IO action, not a list of them.
>
> > printTable :: Foo -> [IO ()]
> > printTable [] = []
> > printTable (x:xs) = putStrLn x : printTable xs
> >
> > main :: [IO ()]
> > main = do
> > let tab1 = ...
> > printTable tab1
>
> If you want to convert a list of IO actions into a
> single action which executes each of these in turn, then
> you can use the `sequence' function:
>
> main :: IO ()
> main = do
> let tab1 = ...
> sequence (printTable tab1)
It's actually sequence_ in Haskell '98.
> However, it may make more sense to do the sequencing in
> the `printTable' function itself:
>
> printTable :: Foo -> IO ()
> printTable [] = return ()
> printTable (x:xs) = do { putStrLn x; printTable xs; }
>
> main :: IO ()
> main = do
> let tab1 = ...
> printTable tab1
It's even easier with mapM_, which obviates the need for printTable:
> main :: IO ()
> main = do
> let tab1 = ...
> mapM_ putStrLn tab1
-Paul
