On Fri 22 Sep, [EMAIL PROTECTED] wrote: > Why does this code fragment print a continous stream of b's? > I thought it should print some alternation of a's and b's. Sorry, I don't know the answer, but this post reminds me of something I'd been meaning to ask.. I seem to remember reading that Concurrent Haskell only needs 1 stack, rather than 1 stack per thread. Is this true? (If so I can't see how this can be done using preemptive thread switching.) Regards -- Adrian Hey
