Re: [Haskell] Syntax Q: How do you share RHS's in case expressions!?

[Ben Rudiak-Gould]

Ryan Newton wrote:
 For example, in OCaml:
 match 3 with 3 -> 99 | 4 -> 99
 Can be abbreviated
 match 3 with 3 | 4 -> 99
 But I have had no luck figuring out how to do the same thing with:
 case 3 of 3 -> 99; 4 -> 99
You can do this:
  let rhs = (some complicated expression) in
  case 3 of
    3 -> rhs
    4 -> rhs
The complicated expression won't be evaluated unless one of the 
appropriate case alternatives is chosen.

-- Ben
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