On 4/18/05, Lloyd Allison <[EMAIL PROTECTED]> wrote: > Is it possible to define Y in Haskell (pref' H98) -- > and get it to pass type checking?
I believe that y f = f (y f) is the normal way to do it. .trev _______________________________________________ Haskell mailing list Haskell@haskell.org http://www.haskell.org/mailman/listinfo/haskell
