On 08 Jan 2006 16:37:47 +0100, Peter Simons wrote: >Bruno Oliveira writes:
> >> class Foo o where > >> (:+) :: o -> o -> o >The Haskell report specifies in section "2.4 Identifiers and >Operators": > An operator symbol starting with a colon is a constructor. >Think of ':' as a character that is interpreted as "uppercase"; >you can't use it to start a function or variable name. Then this declaration should be rejected as invalid, right? That's why I think this is a parsing bug... Cheers, Bruno _______________________________________________ Haskell mailing list Haskell@haskell.org http://www.haskell.org/mailman/listinfo/haskell
