I think your formulation is slightly off. Try .5*(log(1+r)-log(1-r)); (Note
the extra parens). This provides the same result as atanh(r), which is another
way of computing the Fisher Z transform, and is not the same as
.5*log(1+r)-log(1-r).
-Aaron
> On Mar 30, 2015, at 1:00 PM, [email protected] wrote:
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> 1. netmats in HCP (Yizhou Ma)
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> ----------------------------------------------------------------------
>
> Message: 1
> Date: Mon, 30 Mar 2015 11:02:39 -0500
> From: Yizhou Ma <[email protected]>
> Subject: [HCP-Users] netmats in HCP
> To: "[email protected]" <[email protected]>
> Message-ID:
> <CAKJqZMrM74HMMD8nfD4Q7qygeS=jt56kffu0aur69kguufw...@mail.gmail.com>
> Content-Type: text/plain; charset="utf-8"
>
> Dear HCP experts,
>
> I am trying to reproduce the individual netmats from HCP500-PTN so that I
> am sure where the numbers come from. I used individual node timeseries in
> /ts2/subjID and did correlation in matlab. I then used fisher's z
> transformation: .5*ln(1+r)-ln(1-r). The resulting netmat is different from
> what is provided in *_netmat1/. However, they almost have a linear
> relationship. It seems to me that HCP is not using the same z
> transformation I have used. The transformation seems more like
> 7*ln(1+r)-ln(1-r).
>
> I have downloaded FSLNets but could not identify which function was used to
> generate individual netmats in the first place. The example script seems to
> be about group-level netmats only.
>
> Could you please share with me how exactly the numbers in individual
> netmats were generated?
>
> Thanks,
> Cherry
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