Thomas, I am afraid this high-level Fortran API may not be working properly (regression test is missing; I am filing a bug report).
Meanwhile, you may try to use Fortran function h5tget_member_name_f http://www.hdfgroup.org/HDF5/doc/RM/RM_H5T.html#Datatype-GetMemberName to get the correct name size. Unfortunately you will need to open the table with the h5dopen_f call and get a type identifier using h5dget_type_f before you can use h5tget_member_name_f. Elena On Jul 1, 2010, at 12:49 PM, Thomas Robitaille wrote: > Hello, > > I am using the high-level table API to read in a table from an HDF5 data > file. I am using the h5tbget_field_info_f routine, which I need to supply > with an empty array for the field names. Is there a robust way to find out > what length to make the individual field names in the array? I found that in > the case I am looking at, I need to define > > character(len=255),allocatable :: field_names(:) > > If I do not use a value of 255, then the field_names have whitespace in the > wrong places, and if the length is too short I even get malloc errors. > Therefore, it seems that the length has to match the length used to store the > data in the file. Therefore, is there a way to find out in advance the length > needed for the field names before calling h5tbget_field_info_f? > > Just to be clear, I am using h5tbget_table_info_f to get nfields which I can > use to allocate field_names, but I am trying to find out the value for the > length of each individual element in field_names(:) > > Thanks in advance for any help, > > Thomas > > > _______________________________________________ > Hdf-forum is for HDF software users discussion. > [email protected] > http://mail.hdfgroup.org/mailman/listinfo/hdf-forum_hdfgroup.org
_______________________________________________ Hdf-forum is for HDF software users discussion. [email protected] http://mail.hdfgroup.org/mailman/listinfo/hdf-forum_hdfgroup.org
