Agree. 

On Dec 10, 2010, at 4:26 PM, Rhys Ulerich wrote:

>> Why not add a helper method to define a defacto
>> type for it to HDF5 just as many of these other users are currently
>> doing ABOVE HDF5? That way, they all don't wind up essentially
>> duplicating the same effort?
> 
> To be fair, because there's no one-size-fits-all complex number
> solution outside Fortran, a one-size-fits-all cross-language HDF5
> helper method to define a complex type would be difficult to get
> right.  Not technically difficult, just socially difficult.
> 
> - Rhys
> 
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