Hello!
In the Hadoop 0.20, you'll do the following:
In the mapper class
1. create a field "job" of type JobConf
2. in the "configure" method of the mapper class
initialize the job with the received argument
3. In the map function you'll get the processed file name by using the
property map.input.file (example job.get("map.input.file"))
I hope that this help.
Regards,
Florin
--- On Fri, 7/22/11, Florin P <florinp...@yahoo.com> wrote:
From: Florin P <florinp...@yahoo.com>
Subject: Obtain the filename that is procesed by Map class when
CombineFileInputFormat is used
To: hdfs-user@hadoop.apache.org
Date: Friday, July 22, 2011, 8:34 AM
Hello!
I would like to ask you, how can you obtain the filenames that is processed
by Map class when CombineFileInputFormat is used?
As far as I know when using CombineFileInputFormat, multiple files will be
processed by the same mapper. In my case, I would like to know how to obtain
these file names.
I look forward for your answers. Thank you.
Regards,
Florin
