Hi Zhe, I¹m glad you brought this up and thank you Greg for the
clarification.

Best Regards

Raquel



Raquel Viula

PhD Researcher



TU Delft | Faculty of Architecture and the Built Environment |

Architectural Engineering and Technology

Julianalaan 134, 2628 BL Delft, The Netherlands | P.O. Box 5043 2600 GA Delf

From:  Zhe Kong <[email protected]>
Reply-To:  High Dynamic Range Imaging <[email protected]>
Date:  Saturday 28 January 2017 02:09
To:  <[email protected]>
Subject:  Re: [HDRI] Convert equisolidangular to equiangular projection

Sorry about the confusion I brought up. I got this wrong information from
the manufacturer. If I recall my previous experience, Sigma f/3.5 matches
Radiance -vta pretty well. The current mismatch might be caused by the
camera coordinate in the simulation.
Anyway, Happy Chinese New Year, everyone!


Zhe 


 
On Fri, Jan 27, 2017 at 10:11 AM,  <[email protected]> wrote:
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>    1. Re: Convert equisolidangular to equiangular projection
>       (Gregory J. Ward)
> 
> 
> ----------------------------------------------------------------------
> 
> Message: 1
> Date: Fri, 27 Jan 2017 08:10:53 -0800
> From: "Gregory J. Ward" <[email protected]>
> To: High Dynamic Range Imaging <[email protected]>
> Subject: Re: [HDRI] Convert equisolidangular to equiangular projection
> Message-ID: <[email protected]>
> Content-Type: text/plain; charset="windows-1252"
> 
> Raquel points out an important error in this discussion's terminology.  The
> "equidistant" fisheye does indeed correspond to the "-vta" view type in
> Radiance.  However, the "-vth" type corresponds to a hemispherical projection,
> which very few commercial fisheye lenses realize.  In particular, the
> equisolidangle projection is much closer to "-vta" than it is to "-vth".  If
> your lens is equisolidangle, then you need to use the fisheye_corr.cal script
> or similar to convert it to an equidistant projection.
> 
> I have not implemented the equisolidangle projection, though there is a third
> fisheye type (-vts) which is called "stereographic", although we prefer the
> term "planisphere" projection to avoid confusion with stereo views.  This does
> not correspond to any commercial lenses to my knowledge, but I'd be interested
> to hear of one.
> 
>> > From: Raquel Viula <[email protected]>
>> > Date: January 27, 2017 5:49:57 AM PST
>> >
>> > Hi all,
>> > Thank you for raising this topic and sharing your views. I?m using the
>> output of a Sigma f=4.5mm F/2.8 for several analysis including DGP via
>> Evalglare that should require a -vth or -vta view, so this is critical
>> information for me.
>> > May I ask why people refer to -vth as equi-solid angle and not
>> hemispherical as it is defined in Radiance?s rpict man page?
>> > My understanding from that page and from Axel Jacobs' presentation sent via
>> the link just before is that there isn't a Radiance description for the
>> equi-solid angle view.
>> >
>> > Best Regards
>> >
>> > Raquel Viula
>> > PhD Researcher
>> >
>> > TU Delft | Faculty of Architecture and the Built Environment |
>> > Architectural Engineering and Technology
>> > Julianalaan 134, 2628 BL Delft, The Netherlands | P.O. Box 5043 2600 GA
>> Delft
>> >
>> > From: Claus Br?ndgaard Madsen <[email protected]>
>> > Reply-To: High Dynamic Range Imaging <[email protected]>
>> > Date: Friday 27 January 2017 13:49
>> > To: High Dynamic Range Imaging <[email protected]>
>> > Subject: Re: [HDRI] Convert equisolidangular to equiangular projection
>> >
>> >
>> >
>> > Hi everyone,
>> >
>> > Some years ago I tested my Sigma 8mm lens, f3.5.
>> >
>> > At the time I found several sources online claiming it to be equi-solid
>> angle (-vth), but it didn?t match my personal experiences with the lens, so I
>> tested it.
>> >
>> > My tests showed it to be equidistant (-vta), i.e. identical to the angular
>> fish eye projection in RADIANCE.
>> >
>> > So, in my experience, the 8mm Sigma lens is equidistant.
>> >
>> > Cheers,
>> > Claus
>> >
>> >
>> >
>> > Claus B. Madsen
>> > Assoc. Prof., Ph.D. | Department of Architecture and Media Technology
>> >
>> > Phone: +45 9940 8788 <tel:%2B45%209940%208788>  | E-mail: 
>> > [email protected]
>> > Aalborg University | Rendsburggade 14 | 9000 Aalborg | Denmark
>> >
>> > Employee No.: 107255 | Vat No.: DK29102384
>> >
>> >
>> > From: "J. Alstan Jakubiec" <[email protected]>
>> > Reply-To: High Dynamic Range Imaging <[email protected]>
>> > Date: Friday, 27 January 2017 at 11.33
>> > To: "[email protected]" <[email protected]>
>> > Subject: Re: [HDRI] Convert equisolidangular to equiangular projection
>> >
>> > A little followup that is worth noting is that Axel Jacobs measured the
>> Sigma 4.5mm and found it to have an equi-solid angle projection. See his
>> presentation here:
>> https://www.radiance-online.org/community/workshops/2012-copenhagen/Day2/Jaco
>> bs/Jacobs-AJ09-HDR_Radiance_WS-2012.pdf
>> >
>> > Alstan
>> >
>> >
>> > On 1/27/2017 6:26 PM, J. Alstan Jakubiec wrote:
>> > Hi Tobias,
>> >
>> > I just purchased a pair of Sigma 8mm f/3.5's for my work, but I haven't
>> measured them for vignetting and angular verification yet. It is on my to do
>> list :). I will be disappointed if they are equi-solid angular however. Will
>> let you know sometime after the Lunar new year.
>> >
>> > Alstan
>> >
>> >
>> > On 1/27/2017 6:17 PM, Tobias Porsch wrote:
>> > Hi Alstan,
>> >
>> > I'm not sure if your below description is correct.
>> > In my experience it's exactly the opposite. The Sigma f=8mm F/3.5 lens is
>> an equi-solid angle (-vth) and the Sigma f=4.5mm F/2.8 is an equi-distant
>> (-angular) (-vta) lens.
>> > Can you please double-check that issue for me?
>> >
>> > Cheers
>> > Tobias
>> >
>> > Von: J. Alstan Jakubiec [mailto:[email protected]]
>> > Gesendet: Donnerstag, 26. Januar 2017 06:58
>> > An: [email protected]
>> > Betreff: Re: [HDRI] Convert equisolidangular to equiangular projection
>> >
>> > Hi Zhe,
>> >
>> > As far as I am aware, the Sigma 8mm f/3.5 is an equi-angular (-vta) lens,
>> and the Sigma 4.5mm f/2.8 is an equi-solid angle (-???) lens. I am having
>> trouble finding a source from Sigma right now, but Cauwerts, Bodart and
>> Deneyer's paper says so.
>> >
>> > That said, if you do end up with an equi-solidangle image, I have a python
>> script that converts equi-solid angle to equi-angle for each source jpeg
>> while maintaining the EXIF data. I used this to convert equi-solidangle
>> images from my Canon 8-15mm fisheye lenses.
>> >
>> > Best,
>> > Alstan
>> >
>> > On 1/26/2017 8:48 AM, Gregory J. Ward wrote:
>> > Hi Zhe,
>> >
>> > You should be able to apply the fisheye_corr.cal file I gave you earlier to
>> correct the distortion and make it an angular fisheye image that pinterp
>> works with.  (Why you need pinterp, I am not sure.)  The command is as
>> suggested in the fisheye_corr.cal file itself:
>> >
>> >  pcomb -f fisheye_corr.cal -o fisheye.hdr \
>> >         | getinfo -a "VIEW= -vta -vh 180 -vv 180" \
>>> >         > corrected.hdr
>> >
>> > This will also crop the area outside of 180? to black, assuming that is
>> what you want.  It assumes that you have already cropped the image to a
>> minimum square area.  You should apply vignetting correction and absolute
>> calibration first.
>> >
>> > Cheers,
>> > -Greg
>> >
>> > From: Zhe Kong <[email protected]>
>> > Date: January 25, 2017 1:15:49 PM PST
>> >
>> > Dear list:
>> > I am trying to compare HDR images and simulated luminance maps. Since I use
>> SIGMA 8mm 1:3.5 for Canon, I need to convert equisolid-angular to equiangular
>> project. I see very useful information from the post below:
>> >
>> > 
>> https://www.radiance-online.org:447/pipermail/radiance-general/2015-August/01
>> 1184.html
>> >
>> > However, I still have some questions need to figure out.
>> > 1) pinterp does not include equisolid-angular projection, so a equation
>> needs to be applied to the function. Greg mentioned this simple expression,
>> sin(theta)/theta, but I am still confused. Could anyone offer me the command?
>> >
>> > 2) The post discussed the steps of processing HDR images. If I get it
>> right, the steps following "adjust exposure" are vignetting correction,
>> adding view information, converting project from equisolidangular to
>> equiangular, then calibrating the image. I use a GOSSEN Starlite 2 to record
>> the luminance value on a grey card for calibration. My question is, should I
>> calibrate the image before or after converting fisheye projection?
>> >
>> > Any suggestions or explanation would be appreciated.
>> > Zhe
>> >
>> >
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-- 
Zhe Kong
PhD Student
University of Wisconsin - Milwaukee
School of Architecture and Urban Planning
2131 E. Hartford Ave, Milwaukee, WI 53211
Office 327
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