Joel E. Denny wrote:
If we start "parsing" namespace names, we will have a million
new questions to answer. What is the output of "::foo",
I figured the namespace name is meant to be relative to the global
namespace, so a leading "::" is implicit if not specified.
I'm not sure if this is true. Could it be that without "::"
it's relative to the namespace the call was made from instead
of the global namespace?
I assume so because I had lex() in its own namespace and yylex
defined to "lex" working together before.
Sebastian
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