HI
@Hans. thanks
I saw the comments in the code:
/* Variants are always initialized to an empty instance of the
correct type. The default '$$ = $1' action is NOT applied
when using variants. */
so seems we are ok.
min
On Fri, Aug 19, 2016 at 9:53 AM, Hans Åberg <haber...@telia.com> wrote:
>
> > On 19 Aug 2016, at 15:45, Min Wang <mingew...@gmail.com> wrote:
>
> > so if every rule has an explicit action, the issue could be avoided,
> right?
>
> Only if the implementation of the C++ parser has been changed, but it may
> not. Check the output C++ source code.
>
>
>
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