> I have no idea. You'd have to study the grammar to see if there > are doing fancy things around yacc_EOF.
declare -p BASH_SOURCE Here is what I got with the above one line bash code (with the newline at the end). The lines with -> are the parsing rules activated. The rest lines are yylex() results. WORD WORD simple_command_element -> WORD simple_command -> simple_command_element simple_command_element -> WORD simple_command -> simple_command simple_command_element WORD simple_command_element -> WORD simple_command -> simple_command simple_command_element \n command -> simple_command pipeline -> command pipeline_command -> pipeline simple_list1 -> pipeline_command simple_list -> simple_list1 simple_list_terminator -> '\n' inputunit -> simple_list simple_list_terminator yacc_EOF inputunit -> yacc_EOF If yacc_EOF were to be removed, do you see how to redesigned this subset of grammar rules? Thanks. (Since this subset is much smaller than the full grammar, I think it should be easy to see how to remove yacc_EOF, yet maintain the same functionality of the grammar?) -- Regards, Peng _______________________________________________ help-bison@gnu.org https://lists.gnu.org/mailman/listinfo/help-bison
