Hi Dan and Andrew,

This problem is an instance of what is called "fractional programming" and is applied in Data Envelopment Analysis among others.

The general form of the problem is:
Max z = [c0 + (c1*x1) + (c2*x2) + ... + (cn * xn)] / [d0 + (d1*x1) + (d2*x2) + ... + (dn * xn)]

s.t.   (ai1*x1) + (ai2*x2) + ... + (ain * xn) = bi        for i = 1,2,...,m

Under certain assumptions, the problem above can be nicely transformed to a standard linear model without the complications of a piecewise linear approximation.

To this purpose, define r = 1 / [d0 + (d1*x1) + (d2*x2) + ... + (dn*xn)].and assume r > 0 for all feasible values of xj. There are tricks to fulfil this assumption: if xj .>= 0, take a (not too) small positive value for d0.

The objective function z cab then be rewritten as follows:

z = c0*r + (c1*x1*r) + (c2*x2*r) + ... + (cn * xn*r)]

Next define yj = r*xj. The maximization problem becomes now:

max z = c0*r + (c1*y1) + (c2*y2) + ... + (cn * yn)].

s.t.  (ai1*y1) + (ai2*y2) + ... + (ain * yn) = r*bi        for i = 1,2,...,m

and d0*r + (d1*y1) + (d2*y2) + ... + (dn*yn) = 1.

Success!

Best regards,

Ivo van Baren



----- Original Message ----- From: "Andrew Makhorin" <[EMAIL PROTECTED]>
To: "Dan Tulk" <[EMAIL PROTECTED]>
Cc: <[email protected]>
Sent: Thursday, November 15, 2007 10:37 AM
Subject: Re: [Help-glpk] (no subject)


I've been using GLPK to solve an optimisation with objective function of the
form

        (c1*x1) + (c2*x2) + ... + (cn * xn)

Is there any way to use GLPK to solve an objective function of the form?

[(c1*x1) + (c2*x2) + ... + (cn * xn)] / [(d1*x1) + (d2*x2) + ... + (dn * xn)]

You cannot use the latter objective directly, because it is non-linear
while glpk allows only linear objectives and constraints. Besides, that
objective is non-convex, so there may be multiple local optima.

Nevertheless, you can reformulate your problem using piecewise linear
approximation of the objective. For example, introducing variables

  p = (c1*x1) + (c2*x2) + ... + (cn * xn)

  q = (d1*x1) + (d2*x2) + ... + (dn * xn)

you can write the objective as follows:

  z = p / q

Let p and q be positive, and you need to minimize z. Instead that you
can minimize the following separable function:

  ln z = ln p - ln q

replacing ln p and ln q by a piecewise linear approximation.

For more details see
http://lists.gnu.org/archive/html/help-glpk/2007-06/msg00005.html .



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