How can I get the upper bound for the rows?

  No.   Row name   St Activity  Lower bound Upper bound Marginal
------ ------------ -- --------- ----------- ----------- --------
    1 constraint1  NL        48          48                  0.2
    2 constraint2  NL        35          35                  0.5
    3 constraint3  NL        24          24                  0.5
    4 constraint4  NL        10          10                  0.5
    5 constraint5  NL         8           8                    1


0.2
0.5
0.5
0.5
1

On Fri, Aug 5, 2011 at 4:38 PM, Andrew Makhorin <[email protected]> wrote:

> > I can't see where the probleme is coming
> >
> > model primar is
> >
> > \* Problem: Unknown *\
> >
> > Minimize
> >  objective: + x_1 + x_2 + x_3 + x_4 + x_5
> >
> > Subject To
> >  constraint1: + 5 x_1 >= 48
> >  constraint2: + 2 x_2 >= 35
> >  constraint3: + 2 x_3 >= 24
> >  constraint4: + 2 x_4 >= 10
> >  constraint5: + x_5 >= 8
> >
> > End
> >
> > I solve and get
> >
> > getObjectiveValue
> > master obj:52.1
> >
> > then I wont to pass a dual solution for this I do
> > GLPK.glp_get_col_dual(lp,colId+1) for all collone and I got this.
>
> Optimal basic solution to your lp I obtained with glpsol is the
> following:
>
> Rows:       5
> Columns:    5
> Non-zeros:  5
> Status:     OPTIMAL
> Objective:  objective = 52.1 (MINimum)
>
>   No.   Row name   St Activity  Lower bound Upper bound Marginal
> ------ ------------ -- --------- ----------- ----------- --------
>      1 constraint1  NL        48          48                  0.2
>     2 constraint2  NL        35          35                  0.5
>     3 constraint3  NL        24          24                  0.5
>     4 constraint4  NL        10          10                  0.5
>     5 constraint5  NL         8           8                    1
>
>   No. Column name  St Activity  Lower bound Upper bound Marginal
> ------ ------------ -- --------- ----------- ----------- --------
>      1 x_1          B        9.6           0
>     2 x_2          B       17.5           0
>     3 x_3          B         12           0
>     4 x_4          B          5           0
>     5 x_5          B          8           0
>
> Note that all columns (variables) are basic at the optimum, so they all
> have zero reduced costs, that is, dual values.
>
>
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