In this example, suppose that I want to print '*' a single time if x[a] is 0 for everyone, and a if x[a] is 1.
(supposing that A is an elemental set, and a is symbolic, and x[a] = 1 for at most one a). Ideas ? Simple formatting but I miss it. Thank you. 2011/11/1 glpk xypron <[email protected]> > Hello Kasper, > > in GMPL "if" is not a statement but an expression. The following > is a valid use of if: > > set A := {1..4}; > param x{A}; > printf {a in A} ( if x[a] then "x[%s] = %d\n" else "" ), a, x[a]; > data; > param x := > 1 0 > 2 2 > 3 0 > 4 1; > end; > > Best regards > > Xypron > > > -------- Original-Nachricht -------- > > Datum: Tue, 1 Nov 2011 15:11:33 +0100 > > Betreff: [Help-glpk] If-then expression: invalid use of reserved keyword > if > > > Hi guys > > > > I was trying to make a simple if-then statement as below, but failed with > > the error: "invalid use of reserved keyword if". > > I then tried searching the archive but the closest I got to an answer, > was > > that it is not allowed to use if-then like this. > > Anyone know a workaround for that? > > I got a lot of 0-entries in 'x' and i simply just want to print the ones > > that is set to 1 > > > > for {r in R} { > > for {s in S} { > > for {i in 1..fr[r]} { > > if x[s,r,i] = 1 then printf "x[%s,%s,%i] = %i\n", s,r,i,x[s,r,i] > > } > > } > > } > > > > Best regards, > > Kasper > > -- > Follow me at http://twitter.com/#!/xypron > > Empfehlen Sie GMX DSL Ihren Freunden und Bekannten und wir > belohnen Sie mit bis zu 50,- Euro! https://freundschaftswerbung.gmx.de > > _______________________________________________ > Help-glpk mailing list > [email protected] > https://lists.gnu.org/mailman/listinfo/help-glpk > -- *Nilo Cesar Teixeira* [email protected]
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