Hi
Sorry but I can figure this out.
What would I do if I have:
set S := s1 s2 s3 s4;
set R := r1 r2 ;
param fr := r1 42
r2 42 ;
var x {s in S, r in R, i in 1..fr[r]}, binary;
and I want to, lets say force x[s1,r2,10] to be 1?
Best regards,
Kasper
On Thu, Nov 10, 2011 at 5:30 PM, Andrew Makhorin <[email protected]> wrote:
> > I got a question regarding a decision var.
> > My problem is that I got this decision var, that is kinda half
> > decision var and half a constant.
> > So my question is, is it possible so define some of the values of a
> > decision var in the data file and let GLPK decide the rest?
> >
> > I know that one way to solve this is just to "subtract" the ones that
> > is set from the problem and then solve the rest, but it would be nice
> > to know if I could do it like that also.
>
> You may fix some decision variables at certain constant values by
> introducing appropriate equality constraints, for example,
>
> var x{j in J};
>
> set C, within J;
>
> s.t. foo{j in C}: x[j] = 3.14159;
>
>
>
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