On Fri, 02 May 2008 09:13:35 +1000, John Bartley K7AAY
<[EMAIL PROTECTED]> wrote:
On May 1, 4:02 pm, [EMAIL PROTECTED] (Bob Proulx) wrote:
John Bartley K7AAY wrote:
> I need to print $1 lines from a file, and then delete that number of
> lines.
> $1 has been derived in the prior line with
> wc -l sourcefile.txt | awk '{$1 /= 4 ; $1 = int($1) ; print $1 }'
That all looks okay. But I would probably personally do it all in the
shell. Try this:
echo $(( $(wc -l < sourcefile.txt) / 4 ))
> I've tried numerous awk and sed statements, a la:
> sed -e -n "$1,p" sourcefile.txt > list.1
> sed -i "$1d" sourcefile.txt
> sed $1q list.txt > list.1 & sed -i $1d sourcefile.txt
> awk "{(FNR < $1); print}" sourcefile.txt > list.1
Try this:
l=$(( $(wc -l < sourcefile.txt) / 4 ))
sed --in-place "1,${l}d" sourcefile.txt
Bob
Dangit, those don't work as you expected with XP and GNUwin32
echo $(( $(wc -l < sourcefile.txt) / 4 ))
The system cannot find the file specified.
l=$(( $(wc -l < sourcefile.txt) / 4 ))
The system cannot find the file specified.
sed --in-place "1,${l}d" sourcefile.txt
sed: -e expression #1, char 7: extra characters after command
To set the output of a command to a variable in cmd.exe, use this hack:
for /f %i in ('"<command>"') do set VARIABLE=%i
So for your problem, here's a solution:
for /f %i in ('"wc -l sourcefile.txt"') do set /a LINES=%i/4
split -l %LINES% sourcefile.txt
"set /a" instructs cmd.exe to evaluate a numerical expression.
PS. John, I replied to your original message in alt.msdos.batch.nt (I was
reading newsgroups in alphabetical order).
--
Kam-Hung Soh <a href="http://kamhungsoh.com/blog";>Software Salariman</a>
