"Michael Tiomkin" <[EMAIL PROTECTED]> writes:
> What is interesting in your case is that the C standard defines the
> type of 'a/b' as 'double', and therefore the same rounding should be
> performed on the result.
No, the C and C++ standards allow this behavior.
>From C99 draft:
6.3.1.8 Usual arithmetic conversions
[...]
[#2] The values of floating operands and of the results of
floating expressions may be represented in greater precision
and range than that required by the type; the types are not
changed thereby.45)
____________________
45)The cast and assignment operators are still required to
perform their specified conversions as described in
6.3.1.4 and 6.3.1.5.
--
__("< Marcin Kowalczyk
\__/ [EMAIL PROTECTED]
^^ http://qrnik.knm.org.pl/~qrczak/
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