I've some code here that works fine on g++ 3.2.3, and when I compiled
it under g++ 3.4.6, it failed to compile. Here is a basic layout of
the code (albeit very simplified).
class Base
{
public:
class InnerBase
{
public:
InnerBase(const Base* ) { }
};
};
template<class T>
class derived_first : public Base::InnerBase
{
public:
derived_first(T* p = 0);
};
template<class T>
derived_first<T>::derived_first(T* p)
: Base::InnerBase(p)
{
}
class derived_second : public Base
{
public:
derived_second() {}
}
int main(int argc, char** argv)
{
derived_first<derived_second> d;
return 0;
}
Whenever I compile it with gcc-3.4.6 it complains about the
Base::InnerBase(p) line.
Saying that there's no match for it
derived_first<T>::derived_first(T*) [T = derived_second]
No call that matches
nearest match: Base::InnerBase(Base*)
I've heard that gcc/g++ 3.4 is more strict with templates, using the
two-phase lookup procedure, which seems to break a lot of old template
code. I'm just wondering is there anyway to get this to compile
correctly under the new standard.
For now I've a small hack in. I added the constructor
Base::InnerBase(void* v), and it works fine (but I'd like to get the
correct constructor called).
Any help is much appreciated.
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