Ulrich Eckhardt wrote:
> Larry Smith wrote:
>> // hmmm, pointers on 64 bit hdw are 'long',
>> // not 'long long'.
>> // int is 32 bits, long is 64 bits, ptr is
>> // 64 bits.
>
> Sorry, but that is not universally true. You can be reasonably sure that a
> pointer has the same size as a size_t or a ptrdiff_t, but other than that
> all bets are off. Now, the LLP64 model makes the long long and pointers 64
> bits, while long stays 32 bits. The LP64 model uses 64 bit long and
> pointers, which is what Linux uses on 64 bit hardware.
>
My comment is based on the hdw/OS combo's we target:
SPARC_64/Solaris, PPC_64/SUSE, X86_64/SUSE, & X86/SUSE.
On the 64 bit hdw using 'g++ -m32' longs & ptrs are both 32 bits;
and using 'g++ -m64' longs & ptrs are both 64 bits.
Since the OP is using X86_64/Redhat, I made the
leap that it would be the same as what we're using.
But maybe it's not.
>> printf("%u = sizeof int\n", sizeof(int) );
>> printf("%u = sizeof long\n", sizeof(long) );
>> printf("%u = sizeof ptr\n", sizeof(void *) );
>> printf("%u = sizeof long long\n", sizeof(long long) );
>
> FYI: with 64 bit size_t and 32 bit unsigned, you have a mismatch between
> the printf arguments and its format string. Did you compile with any
> warnings?
>
Yes, those format specifiers are wrong - sorry...
It was late & I forgot to use any compiler warning options.
> Uli
>
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