Patrick <[EMAIL PROTECTED]> writes:
> I wanna do a simple xor of two 64 bit variables as in the following
> code fragment:
>
> unsigned long long test0 = 0x8888000000001210LL;
> unsigned long long test1 = 0x88111111111100EFLL;
> unsigned long long test2;
>
> test2 = test0 | test1;
That does OR, not XOR. If you really wanted XOR, time to crack that
intro C book open again.
> printf("0x%016x ",test2);
>
> Unfortuantely only the lower 32 bits of the result are correct as the
> output shows
That's because if you want to print a long (or long long) value,
you must use appropriate printf format. Time to turn on gcc warnings:
$ gcc -Wall junk.c
junk.c: In function 'main':
junk.c:11: warning: format '%016x' expects type 'unsigned int', but argument 2
has type 'long long unsigned int'
> Anyone an idea why the higher 32 bits are not affected by the
> bitoperation?
They are affected, but due to a bug in your program they are not
printed correctly.
Cheers,
--
In order to understand recursion you must first understand recursion.
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