Carsten Fortmann writes: > I need the following expression > > exp(x*x)erfc(x) (1). > > Due to the exp(x*x) (not exp(-x*x)!!!), > this expression returns a nan for large arguments. I found out, that > (1) is in principal given by dawsons integral for purely imaginary > argument. Does anyone know how to obtain this in gsl?
Hello, Apart from constant factors it is 1/gsl_sf_hazard(). See http://www.network-theory.co.uk/docs/gslref/gsl-ref_105.html -- Brian Gough Network Theory Ltd, Publishing the GSL Manual - http://www.network-theory.co.uk/gsl/manual/ _______________________________________________ Help-gsl mailing list [email protected] http://lists.gnu.org/mailman/listinfo/help-gsl
